A little more alchemy

I still need a small alchemical detail worked out. I need to know the formula for lead type. I hope I can look it up. If not, I would need the volume by weight of the three metals (lead, tin, antimony) when liquid and when solid. With those numbers, I should be able to determine the % of each that is needed to create a dimensionally stable alloy.

I'm pretty sure how to do this with Antimony and either one of the other metals:
aV₁T + bV₁A = aV₂T + bV₂A where a and b are the percentage or number of units and V₁T is the volume of tin when liquid per unit and V₂T is the volume of tin when solid per unit. V₁A is the volume of antimony per unit when liquid and V₂A is the volume of antimony per unit when solid.

Then I compute the same formula for Lead and Antimony. Once I have two dimensionally stable alloys, a 50/50 mix of the two alloys should result in a third dimensionally stable alloy of all three metals. So, for example, if the ratio of Tin to Antimony is 3:1 and the ratio of lead to Antimony is 5:1, then the total formula would be 3 parts tin, 5 parts Lead, and 2 parts Antimony. I'd like to see how close the actual formula is to the previously solved formula for a 3 part alloy that is equal inweight per volume to Silver (.803005305cm³ Lead + .105459050cm³ Tin + <.091535645cm³ Antimony result result in 1 cm³ alloy equal in weight to 1 cm³ Silver.