## 02 January 2009

Okay, so here are the questions so far:

I theorize that Gutenberg used his talent in both metalurgy and alchemy (and also perhaps in printing) to hide something from or for the new prelate. This something has remained hidden, in plain sight, to this very day. it is of such value that even today one might start a war to get it.

Regarding the subject of density & weight by volume, Archimedes made the discovery in Syracuse c200BC. It was the origin of "Eureka!"

The bouyant force on the object is equal to the weight of the displaced fluid.

Gold = 19,300kg/m

Lead = 11,340kg/m

Antimony = 6,697kg/m

Tin = 7,310kg/m

The known elements & weights at the time of Gutenberg were:

Copper (9000BCE) 8.92g/cm

Gold (6000BCE) 19.3g/cm

Lead (7000BCE) 11.34g/cm

Silver (5000BCE) 10.49g/cm

Iron (5000BCE 7.84g/cm

Carbon (3750BCE 2.26g/cm

Tin (3500BCE) 7.31g/cm

Sulfur (2000BCE) 1.96g/cm

Mercury (2000BCE) 13.5g/cm

Zinc (1000BCE) 7.14g/cm

Arsenic (800CE) 5.72g/cm

Antimony (800CE) 6.697g/cm

Bismuth(800CE) 9.78g/cm

At the time of Gutenberg, gold was the heaviest substance known and equal weight of an alloy by volume would not be possible.

It might be possible to solve a formula for an alloy that equaled the weight and volume of silver. Using the weight of each element, 11.34x+7.31x+6.697x=10.49; 25.347x=10.49; x=0.41386

In other words, proportions of the following when mixed to an alloy would equal the weight and volume of silver:

4.693 cm

3.025 cm

2.772 cm

Equal to 10.49 cm

I'm sure there is still something missing, but it should come out to the proportion of three base elements mixed together to equal the weight/volume of silver. But it is silver, not gold. Is that the great discovery?

- What was the proportion in the alloy?
- What are the weights of the 3 m3tals and of gold?
- If Gutenberg got the proportions right, could he have
- hidden gold in the alloy?
- discovered another alloy or mixture of elements that mimicked gold?
- What was Gutenberg doing in the second shop that earned him the gratitude of the future prince of Mainz?
- What did Gutenberg cast in the Black River?

I theorize that Gutenberg used his talent in both metalurgy and alchemy (and also perhaps in printing) to hide something from or for the new prelate. This something has remained hidden, in plain sight, to this very day. it is of such value that even today one might start a war to get it.

- What was hidden?
- How much is known about it? and by whom?
- How much of present-day Mainz was there when Gutenberg was? Is there a different city where it is hidden?
- What is the formula?

Regarding the subject of density & weight by volume, Archimedes made the discovery in Syracuse c200BC. It was the origin of "Eureka!"

- When an object is placed in water it appears to be lighter.
- As the object is lowered into the water, the level rises in the tank. That is, the object displaces a volume of water equal to its own volume below the surface.
- Finally, the great synthesis - the weight of water displaced is equal to the weight loss of the object. This is crucial and not obvious. It means that if Archimedes weighed 175 pounds and carefully stepped into a tub filled to the brim, he would spill over, say, 165 pounds of water. His apparent weight in the tub, then would be 175-165 or 10 pounds. That is, his weight loss would be 165 pounds.

The bouyant force on the object is equal to the weight of the displaced fluid.

Gold = 19,300kg/m

^{3}Lead = 11,340kg/m

^{3}Antimony = 6,697kg/m

^{3}Tin = 7,310kg/m

^{3}The known elements & weights at the time of Gutenberg were:

Copper (9000BCE) 8.92g/cm

^{3}Gold (6000BCE) 19.3g/cm

^{3}Lead (7000BCE) 11.34g/cm

^{3}Silver (5000BCE) 10.49g/cm

^{3}Iron (5000BCE 7.84g/cm

^{3}Carbon (3750BCE 2.26g/cm

^{3}Tin (3500BCE) 7.31g/cm

^{3}Sulfur (2000BCE) 1.96g/cm

^{3}Mercury (2000BCE) 13.5g/cm

^{3}Zinc (1000BCE) 7.14g/cm

^{3}Arsenic (800CE) 5.72g/cm

^{3}Antimony (800CE) 6.697g/cm

^{3}Bismuth(800CE) 9.78g/cm

^{3}At the time of Gutenberg, gold was the heaviest substance known and equal weight of an alloy by volume would not be possible.

It might be possible to solve a formula for an alloy that equaled the weight and volume of silver. Using the weight of each element, 11.34x+7.31x+6.697x=10.49; 25.347x=10.49; x=0.41386

In other words, proportions of the following when mixed to an alloy would equal the weight and volume of silver:

4.693 cm

^{3}Lead3.025 cm

^{3}Tin2.772 cm

^{3}AntimonyEqual to 10.49 cm

^{3>}SilverI'm sure there is still something missing, but it should come out to the proportion of three base elements mixed together to equal the weight/volume of silver. But it is silver, not gold. Is that the great discovery?

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